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where N is Newton, KN is KiloNewton, and MN is MegaNewton. As with the longitudinal magic formula, there are lots of zeros in this particular sample case, but let us not confuse particulars with generalities. The formula can account for much more general cases. The first helper is the peak, lateral friction coefficient µyp = a1Fz + a2, measured in inverse Kilos if Fz is in KN. Next is D = µypFz, which is a factor with the form of the Newtonian model: normal force times coefficient of friction. In our sample, a1 is zero, so µyp acts exactly like a Newtonian friction coefficient. In all cases, we should expect a1Fz to be much smaller than a2 so that it will be, at most, a small correction to the Newtonian behaviour. To get the final force, we correct with the following empirical factor:
This has exactly the same form as the empirical correction factor in the longitudinal version, but the component pieces, S, B, and E are different, here.
where As before, we get B from a product, albeit one of greatly different form
where
Almost done; include
To arrive at the final formula
This form is almost identical-in form-to the longitudinal version of the magic formula. The individual sub-components are different in detail, however. The most important input is the slip angle, First, is the EARTH frame, whose axes we write as {X, Y,
Z}. The Z axis is aligned with Earth's gravitation and points downward.
The origin of EARTH is fixed w.r.t. the Earth and the X and Y axes
point in arbitrary, but fixed, directions. A convenient choice at a typical
track might be the centre of start/finish with X pointing along the
direction of travel of the cars up the main straight. All other coordinate
frames ultimately relate back to EARTH, meaning that the location and
orientation of every other frame must be given w.r.t. EARTH, directly or
indirectly. The next coordinate frame is CAR, whose axes we write
as {x, y, z}. This frame is fixed w.r.t. the sprung mass of
the car, that is the body, with x running from tail to nose, y to
driver's right, and z downward, roof through seat. Its instantaneous
orientation w.r.t. EARTH is the heading, The next coordinate frame is PATH. The velocity vector of the
car traces out a curve in 3-dimensional space such that it is tangent to the
curve at every instance. The X-direction of PATH points along the velocity
vector. The Z-direction of PATH is at right angles to the X direction and in the
plane formed by the velocity vector and the Z-direction of EARTH. The Y
direction of PATH completes the frame such that XYZ form an orthogonal,
right-handed triad. The path of the car lies instantaneously in the XY plane of
PATH. PATH ceases to exist when the car stops moving. Path heading
is the angle of the projection of the velocity vector on EARTH's XY w.r.t. the
X-axis of EARTH. Milliken calls this course angle, The next set of coordinate frames is ROADi, where i
varies from 1 to 4; there are four frames representing the road under each
wheel, numbered as 1=Left Front, 2=Right Front, 3=Left Rear, 4=Right Rear. Each
ROADi is located at the force centre of its corresponding
contact patch at the point Ri = (Rix,
Riy, Riz) w.r.t. EARTH. This
point moves with the vehicle, so, more pedantically, the origin of ROADi
is Ri(t) written as a function of time. To get the X
and Y axes of ROADi, we begin with a temporary, flat, coordinate
system called TAi aligned with EARTH and centred at Ri,
then elevate by an angle -90° <
Consider any point P in space with coordinates P = (Px,
Py, Pz) w.r.t. EARTH. A little reflection reveals that
its location w.r.t. TAi is PAi
We pick this matrix by inspection of the figure above or by application of the right-hand-rule (yup, see Britannica) Finally, to bank the system, we need the orthogonal matrix that does not change the X components, but increases the Y and decreases the Z components of first-quadrant points for small, positive angles, namely:
In case you missed it, we snuck in a reliable, seat-of-the-pants method for getting the signs of orthogonal matrices right. In any event, given P and Ri, we compute the coordinates, PRi, of the point P in ROADi as follows:
If the angles are small,
Even at 20 degrees, the errors are only about 6% in the cosine and 2% in the sin, resulting in a maximum error of 12% in the lower right of the matrix. This matrix approximation is suitable for the majority of applications. One feature of orthogonal matrices is that their inverse is their transpose, that is, the matrix derived by flipping everything about the main diagonal running from upper left to lower right. In the small-angle approximation, we get
The right-hand side is very close to the unit matrix because the squares of small angles are smaller, yet. With the inverse matrix we can convert from coordinates in ROADi to coordinates in EARTH:
The last set of coordinate frames is WHEELi.
As with ROADi, there is one instance per wheel. WHEELi
is centred at the wheel hub. Under normal rolling, the coordinates of its origin
in ROADi are WRi = (0, 0, -Ri),
where Ri is the loaded radius of the tyre-wheel combination.
Pedantically, Ri should be corrected for elevation and
banking, but such corrections would be small for ordinary angles-on the order of
At this point, you should create a mental picture of these coordinate frames
under typical racing conditions. Picture a CAR frame yawed at some heading
w.r.t. EARTH-and perhaps pitched and rolled a bit; a PATH frame aligned at some
slightly different path heading; and individual ROAD and WHEEL frames under each
tyre contact patch, where the ROAD frames are perhaps tilted a bit w.r.t. EARTH
and the WHEEL frames are aligned with the wheel planes but coplanar with the
ROAD frames. For a car travelling on a flat road at a stable, flat attitude, the
XY planes of CAR, PATH, and EARTH would all coincide and would differ from one
another only in the yaw angles Now, imagine the X-axis of CAR projected on the XY plane of each WHEEL frame
and translated-without changing its direction-to the origin of WHEEL. The angle
of WHEEL's X axis, which is the same as the plane containing the wheel, w.r.t.
the projection of CAR's X axis, defines the steering angle, At last, we can plot the magic formula:
The horizontal axis measures slip angle, in degrees. The vertical axis measures lateral, cornering force, in Newtons. The deep axis measures vertical load on the contact patch, in KiloNewtons. We can see that these tyres have a peak at about 4 degrees of slip and that cornering force goes down as slip goes up on either side of the peak. On the high side of the peak, we have dynamic understeer, where turning the wheel more makes the situation worse. This is a form of instability in the control system of car and driver. As a final comment, let me say that I am somewhat dismayed that the magic formula does not account for any variation of the lateral force with speed. Intuitively, the forces generated at high speeds must be greater than the forces at low speed with the same slip angles. However, the literature-sometimes explicitly, and sometimes by sin of omission-states that the magic formula doesn't deal with it. One of the reasons is that, experimentally, effects of speed are extremely difficult to separate from effects of temperature. A fast-moving tyre becomes a hot tyre very quickly on a test rig. Another reason is that theoretical data is usually closely guarded and is not likely to make it into a consensus approximation like the magic formula. This is a fact of life that we hope will not affect our analyses too adversely from this point on. |